{"id":1737,"date":"2023-10-25T14:02:40","date_gmt":"2023-10-25T07:02:40","guid":{"rendered":"https:\/\/kettch.net\/?p=1737"},"modified":"2023-10-25T14:06:49","modified_gmt":"2023-10-25T07:06:49","slug":"tuyen-sinh-chuong-trinh-thuc-tap-dieu-duong-nhat-ban","status":"publish","type":"post","link":"https:\/\/kettch.net\/2023\/10\/25\/tuyen-sinh-chuong-trinh-thuc-tap-dieu-duong-nhat-ban\/","title":{"rendered":"Tuy\u1ec3n sinh ch\u01b0\u01a1ng tr\u00ecnh th\u1ef1c t\u1eadp \u0110i\u1ec1u d\u01b0\u1ee1ng – Nh\u1eadt B\u1ea3n"},"content":{"rendered":"\n
Trung t\u00e2m ngo\u1ea1i ng\u1eef AOI v\u00e0 tr\u01b0\u1eddng Cao \u0111\u1eb3ng Y t\u1ebf B\u1eafc Ninh th\u00f4ng b\u00e1o tuy\u1ec3n sinh ch\u01b0\u01a1ng tr\u00ecnh th\u1ef1c t\u1eadp sinh \u0110i\u1ec1u d\u01b0\u1ee1ng – Nh\u1eadt B\u1ea3n.<\/p>\n\n\n\n
Tuy\u1ec3n 50 n\u1eef t\u1eeb 18-33 tu\u1ed5i, t\u1ed1t nghi\u1ec7p t\u1eeb THPT tr\u1edf l\u00ean, \u01b0u ti\u00ean \u0111\u1ed1i t\u01b0\u1ee3ng \u0111\u00e3 ho\u1eb7c \u0111ang h\u1ecdc trung c\u1ea5p, cao \u0111\u1eb3ng v\u1edbi chuy\u00ean ng\u00e0nh \u0111i\u1ec1u d\u01b0\u1ee1ng, h\u1ed9 l\u00fd. Chi\u1ec1u cao t\u1eeb 150cm tr\u1edf l\u00ean, c\u00e2n n\u1eb7ng 43kg tr\u1edf l\u00ean; kh\u00f4ng x\u0103m h\u00ecnh; \u0110\u1ebfn l\u00e0m vi\u1ec7c t\u1ea1i vi\u1ec7n Ph\u00fac l\u1ee3i x\u00e3 h\u1ed9i HEISEIKAI (T\u1ec9nh Saitama – Nh\u1eadt B\u1ea3n) v\u1edbi m\u1ee9c l\u01b0\u01a1ng 35 tri\u1ec7u VN\u0110 (ch\u01b0a bao g\u1ed3m l\u00e0m th\u00eam).<\/p>\n\n\n\n
T\u1ed5ng chi ph\u00ed tham gia ch\u01b0\u01a1ng tr\u00ecnh: 90.000.000 VN\u0110. \u0110\u1eb7c bi\u1ec7t: Tr\u1eeb ngay 30.000.000 vn\u0111 tr\u00ean t\u1ed5ng chi ph\u00ed tham gia ch\u01b0\u01a1ng tr\u00ecnh v\u1edbi nh\u1eefng sinh vi\u00ean \u0111ang h\u1ecdc ho\u1eb7c t\u1ed1t nghi\u1ec7p t\u1ea1i tr\u01b0\u1eddng Cao \u0111\u1eb3ng Y t\u1ebf B\u1eafc Ninh.<\/p>\n\n\n\n
Hotline t\u01b0 v\u1ea5n<\/mark>: Mr \u0110\u1ea1t: 0981 507 166; Mr Minh: 0914 501 237<\/p>\n\n\n\n Chi ti\u1ebft xem trong th\u00f4ng b\u00e1o d\u01b0\u1edbi \u0111\u00e2y<\/p>\n\n\n